How would you prove the identity [math] a^n - b^n = (a-b)(a^{n-1} + a^{n-2}b + ... + b^{n-2}a + b^{n-1})?[/math] - Quora
![automata - Converting the NFA produced from the language $a^nb^n : n\geq 0$ to a DFA to show its regular? Leading to question about pumping lemma. - Mathematics Stack Exchange automata - Converting the NFA produced from the language $a^nb^n : n\geq 0$ to a DFA to show its regular? Leading to question about pumping lemma. - Mathematics Stack Exchange](https://i.stack.imgur.com/D9PBU.jpg)
automata - Converting the NFA produced from the language $a^nb^n : n\geq 0$ to a DFA to show its regular? Leading to question about pumping lemma. - Mathematics Stack Exchange
![inequality - Duplicate - Proof by Ordinary Induction: $a^n-b^n \leq na^{n-1}(a-b)$ - Mathematics Stack Exchange inequality - Duplicate - Proof by Ordinary Induction: $a^n-b^n \leq na^{n-1}(a-b)$ - Mathematics Stack Exchange](https://i.stack.imgur.com/Fziku.png)
inequality - Duplicate - Proof by Ordinary Induction: $a^n-b^n \leq na^{n-1}(a-b)$ - Mathematics Stack Exchange
![If `a\ a n d\ b` are distinct integers, prove that `a^n-b^n` is divisible by `(a-b)` where `n - YouTube If `a\ a n d\ b` are distinct integers, prove that `a^n-b^n` is divisible by `(a-b)` where `n - YouTube](https://i.ytimg.com/vi/kJLjx0CcVOI/maxresdefault.jpg)
If `a\ a n d\ b` are distinct integers, prove that `a^n-b^n` is divisible by `(a-b)` where `n - YouTube
![context free grammar - Deterministic Pushdown Automata for L = a^nb^n | n >=0) Python Program - Stack Overflow context free grammar - Deterministic Pushdown Automata for L = a^nb^n | n >=0) Python Program - Stack Overflow](https://i.stack.imgur.com/AkBDC.jpg)